Just had actually a lecture there wherein the lecturer to be doing review on digital configuration.

You are watching: Indium(iii) ion electron configuration

He proclaimed that the electronic configuration the $$ceIn^3+= 5s^2 3p^1$$

He didn"t incorporate the $ce4d^10$ orbital. He stated it doesn"t matter and if we compose the full E.C out it"s incorrect. It basically goes against everything we studied in first year basic invernessgangshow.net. Likewise I believe he didn"t take into account the reality that $ceIn^3+$ has actually $46 , e^-$ no $49 , e^-$.

Should the electronic configuration not be $$ce 5s^0 4d^10 3p^0= ce 4d^10$$

Can someone shed some irradiate on whether he is right.


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edited Oct 31 "17 at 22:37
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Mithoron
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Patrick MoloneyPatrick Moloney
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Yup, it"s $4d^10$. Post-transition ($p$-block) elements rarely if ever before ionize or even covalently bond your $d$ subshell electrons. Return we usage the bracketed main point designation just for noble gas cores, by the moment we acquire to group 12 or 13 the $d$ electrons are additionally effectively part of the core.


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edited Oct 31 "17 in ~ 19:15
answer Oct 31 "17 in ~ 12:58
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Oscar LanziOscar Lanzi
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