4/5x1-1/6
This deals with adding, subtracting and also finding the least usual multiple.
You are watching: 4/5x1 1/6
Step by action Solution
Reformatting the input :
Changes made to her input need to not affect the solution: (1): "x1" was replaced by "x^1".Step 1 :
1 leveling — 6Equation at the end of step 1 : 4 1 (— • (x1)) - — 5 6
step 2 :
4 simplify — 5Equation in ~ the finish of action 2 : 4 1 (— • x) - — 5 6Step 3 :
Equation in ~ the finish of action 3 : 4x 1 —— - — 5 6Step 4 :
Calculating the Least typical Multiple :4.1 uncover the Least common Multiple The left denominator is : 5 The appropriate denominator is : 6| 5 | 1 | 0 | 1 |
| 2 | 0 | 1 | 1 |
| 3 | 0 | 1 | 1 |
| Product the allPrime Factors | 5 | 6 | 30 |
Least typical Multiple: 30
Calculating multiplier :4.2 calculation multipliers for the 2 fractions signify the Least typical Multiple by L.C.M represent the Left Multiplier through Left_M signify the best Multiplier by Right_M denote the Left Deniminator by L_Deno denote the right Multiplier by R_DenoLeft_M=L.C.M/L_Deno=6Right_M=L.C.M/R_Deno=5
Making identical Fractions :4.3 Rewrite the two fractions into equivalent fractionsTwo fractions are called equivalent if they have the exact same numeric value. For instance : 1/2 and 2/4 space equivalent, y/(y+1)2 and also (y2+y)/(y+1)3 are indistinguishable as well. To calculation equivalent portion , main point the molecule of every fraction, by its particular Multiplier.
L. Mult. • L. Num. 4x • 6 —————————————————— = —————— L.C.M 30 R. Mult. • R.
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Num. 5 —————————————————— = —— L.C.M 30Adding fractions that have actually a typical denominator :4.4 including up the two tantamount fractions add the two tantamount fractions which now have actually a typical denominatorCombine the numerators together, put the sum or distinction over the usual denominator then mitigate to lowest terms if possible:
4x • 6 - (5) 24x - 5 ———————————— = ——————— 30 30