$egingroup$ "Subset of" way something various than "element of". Keep in mind $a$ is likewise a subset the $X$, despite $ a $ not showing up "in" $X$. $endgroup$

Because every solitary element the $emptyset$ is likewise an element of $X$. Or deserve to you surname an facet of $emptyset$ that is not an aspect of $X$?

that"s since there are statements that space vacuously true. $Ysubseteq X$ method for every $yin Y$, we have actually $yin X$. Now is that true the for every $yin emptyset $, we have $yin X$? Yes, the statement is vacuously true, because you can"t pick any $yinemptyset$.

You are watching: Empty set is a subset of every set

You should start indigenous the an interpretation :

$Y subseteq X$ iff $forall x (x in Y ightarrow x in X)$.

Then girlfriend "check" this meaning with $emptyset$ in location of $Y$ :

$emptyset subseteq X$ iff $forall x (x in emptyset ightarrow x in X)$.

Now you need to use the truth-table definition of $ ightarrow$ ; you have actually that :

"if $p$ is *false*, then $p
ightarrow q$ is *true*", because that $q$ whatever;

so, due to the truth that :

$x in emptyset$

is **not** *true*, because that every $x$, the over truth-definition of $
ightarrow$ offers us that :

"for all $x$, $x in emptyset
ightarrow x in X$ is *true*", because that $X$ whatever.

This is the factor why the *emptyset* ($emptyset$) is a *subset* the every set $X$.

See more: What Is The Ongoing Process Of Tearing Down And Rebuilding Bone Matrix Is Called

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edited Jun 25 "19 in ~ 13:51

answered january 29 "14 at 21:55

Mauro ALLEGRANZAMauro ALLEGRANZA

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$endgroup$

1

include a comment |

4

$egingroup$

Subsets room not necessarily elements. The elements of $a,b$ room $a$ and $b$. Yet $in$ and $subseteq$ are various things.

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answered jan 29 "14 in ~ 19:04

Asaf Karagila♦Asaf Karagila

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$endgroup$

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