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3. A data collection that consists of 50 numbers has a minimum worth of 16 and also a maximum worth of 74. Recognize the class limits us

**invernessgangshow.net:**

**discrete**, the class limits are;

16 - 25

26 - 35

36 - 45

46 - 55

56 - 65

66 = 75

**continuous**, the class limits are;

16 to much less than 26

26 to much less than 36

36 to much less than 46

46 to less than 56

56 to less than 66

66 to less than 76

**Step-by-step explanation:**

Given that;

Range that the dataset = maximum worth - minimum value = 74 - 16 = 58

total variety of data set n = 50

Rule :

≥ nsubstitute worth of n

≥ 50

k × log(2) = log( 50 )

k × 0.3010 = 1.69897

k = 1.69897 / 0.3010

k = 5.64

Hence, we have a full of 6 variety of classes needed to be constructed.

so,

class width = 74 - 16 / 6 = 58 / 6 = 9.67

If the Data is **discrete**, the class limits are;

16 - 25

26 - 35

36 - 45

46 - 55

56 - 65

66 = 75

If the Data is** continuous**, the class borders are;

16 to less than 26

26 to less than 36

36 to much less than 46

46 to less than 56

56 to less than 66

66 to much less than 76

5 0

7 month ago

24 crate of crayons wheigh 235.2 onces how countless ounces is each crate of crayobs

svetlana <45>

**invernessgangshow.net:**

9.8

**Step-by-step explanation:**

235.2 divided by 24

7 0

1 year ago

Read 2 more invernessgangshow.nets

Solve the complying with equation because that x: 6(4x+ 1) = 3(x + 8) + 3.

salantis <7>

**invernessgangshow.net:**

x = -1/7 Or 0.143 (3 dec)

**Step-by-step explanation:**

6(4x + 5) = 3(x + 8) + 3

= 24x + 30 = 3x + 24 + 3

24x + 30 = 3x + 27

21x + 30 = 27

21x = -3

21x/21 = -3/21

x = -1/7

Or 0.143 (3 dec)

3 0

10 month ago

Read 2 much more invernessgangshow.nets

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