Xe would be your main atom, O is attached come it through a doublebond and also your two Fs space attached it is in a single bond.

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There would certainly be 3 Lone Pair (LP) electrons roughly F, 2 roughly O,and 2 approximately Xe. Why ? there is no valance to this molecule for this reason youwant to accomplish the formal fee to it is in 0. Formal charge =(#electrons in floor state) - < (free electrons) - 1/2 (bondingelectrons)>.

Formal charge for F, would desire 0 so

0 = 7 - = 7 - (? +1) = 7 - ? - 1

? = 6, therefore 3 lone pairs roughly fluorines.

Formal charge for O, would want 0 so

0 = 6 - ...

? = 4, therefore 2 LP about oxygen

Formal charge for Xe, again we want it to be 0 so,

0 = 8 - .....

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? = 4, thus 2 LP around Xe.

Kind the a weird collection up (since Xe does not follow the octectrule), but it works out =)

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