Xe would be your main atom, O is attached come it through a doublebond and also your two Fs space attached it is in a single bond.
You are watching: Xef2o lewis structure with formal charges of zero
There would certainly be 3 Lone Pair (LP) electrons roughly F, 2 roughly O,and 2 approximately Xe. Why ? there is no valance to this molecule for this reason youwant to accomplish the formal fee to it is in 0. Formal charge =(#electrons in floor state) - < (free electrons) - 1/2 (bondingelectrons)>.
Formal charge for F, would desire 0 so
0 = 7 - + 1/2 (2) > = 7 - (? +1) = 7 - ? - 1
? = 6, therefore 3 lone pairs roughly fluorines.
Formal charge for O, would want 0 so
0 = 6 - + 1/2 (4) >...
? = 4, therefore 2 LP about oxygen
Formal charge for Xe, again we want it to be 0 so,
0 = 8 - + 1/2 (8)>.....
See more: How Many Lines Of Symmetry Does A Square Have? ? How Many Lines Of Symmetry Does A Square Have
? = 4, thus 2 LP around Xe.
Kind the a weird collection up (since Xe does not follow the octectrule), but it works out =)
Wiki User∙ 10y ago
This prize is: