Firstly, we will have to calculate the number of moles. To perform this, we make use of the ideal gas equation
PV = nRT
n = PV/RT
The parameters have the adhering to values according to the question:
P = 780mmHg, we transform this come pascal.
760mHG = 101325pa
780mmHg = xpa
x = (780 * 101325)/760 = 103,991 Pa
V= 400ml = 0.4L
T = 135C = 135 + 273.15 = 408.15K
n = ?
R = 8314.463LPa/K.mol
Substituting this values right into the equation yields the following:
n = (103991 * 0.4)/(8314.463 * 408.15)
= 0.012 mole
Now we understand 1 mole consists of 6.02 * 10^23 molecules, hinvernessgangshow.netce, 0.012moles will contain = 0.012 * 6.02 * 10^23 = 7.38 * 10^21 molecule
You are watching: How many molecules of n2 are in a 400.0 ml container at 780 mm hg and 135°c?
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e-lub <12.9K>6 month ago
8 0
Answer: The number of nitroginvernessgangshow.net molecules in the container are 
Explanation:
To calculation the mole of gas, we usage the equation givinvernessgangshow.net by right gas i m sorry follows:
where,
P = push of the gas = 780 mmHg
V = Volume the the gas = 400.0 mL = 0.4 together (Conversion factor: 1 together = 1000 mL)
T = Temperature the the gas =
R = Gas constant =
n = number of moles of nitroginvernessgangshow.net gas = ?
Putting values in over equation, we get:
According come mole concept:
1 mole that a compound includes
So, 0.01226 mole of nitroginvernessgangshow.net gas will contain =
Hinvernessgangshow.netce, the variety of nitroginvernessgangshow.net molecules in the container space
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