We would should let u = x^2 and use middle term factorization first. Let"s carry out this:

if u = x^2, climate x^4 + 8x^2 – 9 would certainly be


Middle ax factorization of this is:


now replacing ago u = x^2:


Using the formula a^2 - b^2 = (a+b)(a-b), we have the right to write (x^2 - 1) as (x+1)(x-1).

So, the final factored form is: (x^2+9)(x-1)(x+1)

You are watching: What is the completely factored form of x4 + 8x2 – 9?



step-by-step explanation:

since both terms room perfect squares, variable using the distinction of squares formula, a 2 − b 2 = ( a + b ) ( a − b ) a 2 - b 2 = ( a + b ) ( a - b ) whereby a = x a = x and b = 1 b = 1 . ( x + 1 ) ( x − 1 ) ( x 2 + 9 )



The given duty is


Split the center term


Factor through grouping;


Factor more to get:


Apply difference of 2 squares to get:

ANSWERThe correct answer is BEXPLANATIONWe desire to variable completely,
We deserve to rewrite the over expression in the form.
We deserve to think the this expression together a quadratic trinomial in
We need to separation the middle term with determinants of -9 the adds as much as 8.
We factorize to obtain,
We factor further to obtain,
We apply difference of 2 squares ~ above the leftmost variable to obtain,

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It takes some trial and errorTo uncover the factored form, you recognize that the style will look at like (x^n +/- a) (x^n +/- b) because the expanded kind has x^4, the first part of each expression in parentheses will it is in x^2 due to the fact that x^2 * x^2 will give you x^4Then you have to figure out, just how will you gain -9 in the expanded form? The "a" and "b" components of each expression will have to multiply to same -9.Factors the -9 will certainly be -3*3 or -1*9 or -9*1Also, consider the 8x^2 component - together it relates to finding the factors of 9. The parts of the expression that result in 8x^2 in the expanded form ...a*x^2 + b*x^2 = 8x^2If girlfriend think about this, you recognize the a and b will = -1 and also 9 because you likewise have to add the expressions through x^2 to acquire 8x^2, and 3 and 3 would not provide you the 8x^2 and also neither would nor would certainly -9 and 1.Final factored type is(x^2 - 1) (x^2 + 9)