nitrogen gas is define as N2. Its moleculer fixed will become 28. Because that its one mole it is the 28gram. According to mole concept in one mole over there is 6.022*10^23 moles space present. Therefore mass the 1 molecule of nitogen gas is 28/(6.022*10^23) gram. Solve it and u will gain answer.

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Actually massive of 1 atom the nitrogen is 14 u(u=atomic mass unit) massive of 1 mole=mass of 1 atom that nitrogen * Avagadro"s no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm
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1 mole that Nitrogen has actually 28 g mass. As Nitrogen gas is consisted of of 2 Nitrogen aspects Each nitrogen has Atmoic massive 14 g so N2 will have actually 2x14 = 28 g.
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As we know that no. Of moles = offered mass/molar mass additionally no. Moles = no.of particles(atoms,molecules etc)/avogadro no.(No) together we know Avogadro"s number=6.023*10^23 for this reason no. Of moles=1/6.023*10^23 molar massive of nitrogen = 14*2=28 so no. Of mole = mass/28 1/6.023*10^23=mass/28 mass=28/6.023*10^23...
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Nitrogen always exists as a dimer therefore the fixed of the molecule is to it is in calculated by multiplying atomic mass that nitrogen by 2 which way 14*2=28
Nitrogen molecule mass is 28 1mole that n2 is 28gram because that 1molecule the nitrogen divide 28by avagadro number 6.022 10^23 for this reason ans will be 28/6.022 10^23=4.64 10^-23
14 grams fixed = number of moles x molar mass 1 mole= relative mass in grams of that specific element
mass of 1 mole=mass that 1 atom that nitrogen * Avagadro"s no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm
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