There is just one structure feasible because that a tetrahedral molecule v such a formula, under the supposition the A is in the facility of the tetrahedredon. In this situation X and Y are in the vertices the the tetrahedron.

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If you draw several figures an altering the place of the X"s and the Y around the center (A), you will view that all room equivalent.This is the case of the product CH3Cl, named chloromethane, which, for the same reason provided above, does not have isomers.

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