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3. A data collection that consists of 50 numbers has a minimum worth of 16 and also a maximum worth of 74. Recognize the class limits us
invernessgangshow.net:
discrete, the class limits are;
16 - 25
26 - 35
36 - 45
46 - 55
56 - 65
66 = 75
continuous, the class limits are;
16 to much less than 26
26 to much less than 36
36 to much less than 46
46 to less than 56
56 to less than 66
66 to less than 76
Step-by-step explanation:
Given that;
Range that the dataset = maximum worth - minimum value = 74 - 16 = 58
total variety of data set n = 50
Rule :
≥ nsubstitute worth of n
≥ 50
k × log(2) = log( 50 )
k × 0.3010 = 1.69897
k = 1.69897 / 0.3010
k = 5.64
Hence, we have a full of 6 variety of classes needed to be constructed.
so,
class width = 74 - 16 / 6 = 58 / 6 = 9.67
If the Data is discrete, the class limits are;
16 - 25
26 - 35
36 - 45
46 - 55
56 - 65
66 = 75
If the Data is continuous, the class borders are;
16 to less than 26
26 to less than 36
36 to much less than 46
46 to less than 56
56 to less than 66
66 to much less than 76
5 0
7 month ago
24 crate of crayons wheigh 235.2 onces how countless ounces is each crate of crayobs
svetlana <45>
invernessgangshow.net:
9.8
Step-by-step explanation:
235.2 divided by 24
7 0
1 year ago
Read 2 more invernessgangshow.nets
Solve the complying with equation because that x: 6(4x+ 1) = 3(x + 8) + 3.
salantis <7>
invernessgangshow.net:
x = -1/7 Or 0.143 (3 dec)
Step-by-step explanation:
6(4x + 5) = 3(x + 8) + 3
= 24x + 30 = 3x + 24 + 3
24x + 30 = 3x + 27
21x + 30 = 27
21x = -3
21x/21 = -3/21
x = -1/7
Or 0.143 (3 dec)
3 0
10 month ago
Read 2 much more invernessgangshow.nets
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