## A bag includes 8 white marbles, 6 red marbles and 4 blue marbles. How many blue marbles need to be included to the bag so the the probability of

A bag includes 8 white marbles, 6 red marbles and 4 blue marbles. How many blue marbles should be added to the bag so that the probability of selecting a blue marble is 1/2?

**Answer:**

The yes, really answer would certainly be 10 marbles.

You are watching: A bag contains 6 red marbles 6 white marbles and 4 blue marbles

**Step-by-step explanation:**

**1. ***we had started turn off by adding ***8+4+6 ***to get the total variety of marbles. If we carry out that, we will gain that there are ***18 marbles in total.**

**2. ***here is where the rather went wrong. If us say the we need 5 blue marbles to get 9/18 blue marbles, you space wrong. **This is because we have to include 5 come the total number of marbles together well. **Then we get 9/23 marbles. I m sorry is clearly not 1/2, *

**3. ***However, if we multiply 5 through 2, we obtain 10 blue marbles. If we add 10 to the initial 18, we gain ***28 full marbles**. *Now if we include 10 to 4 we obtain 14 blue marbles. *

**SUCCESS!!!**

*14/28 blue marbles is 1/2, as such we must include 10 blue marbles.*

trungdung22

0

answer

Answer:

5 marbles

Step-by-step explanation:

A bag contains

8 white marbles

6 red marbles

4 blue marbles.

Total variety of marbles is :

8 + 6 + 4

= 18 marbles

Based top top this existing proportion

The Probability of choosing a blue marble = variety of blue marbles/ Total variety of marbles

In order because that the Probability of choosing a blue marble to it is in 1/2

The variety of blue marbles has to be:

= 18 marbles × 1/2

= 9 blue marbles

From the question we have actually 4 blue marbles, hence:

9 blue marbles – 4 blue marbles

= 5 blue marbles

Therefore, 5 blue marbles should be added to the bag so the the probability of picking a blue marble is 1/2.

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